fix(curriculum): remove before/after-user-code from rosetta challenges 6-10 (#66390)

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Sem Bauke 2026-03-12 19:26:08 +01:00 committed by GitHub
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5 changed files with 95 additions and 95 deletions

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@ -21,6 +21,24 @@ must reference documentation indicating that the algorithm is something better
than a simple minimum length algorithm.
</pre>
# --before-each--
```js
const text =
`Wrap text using a more sophisticated algorithm such as the Knuth and Plass TeX algorithm.
If your language provides this, you get easy extra credit,
but you ''must reference documentation'' indicating that the algorithm
is something better than a simple minimum length algorithm.`;
const wrapped80 = wrap(text, 80);
const wrapped42 = wrap(text, 42);
const firstRow80 =
'Wrap text using a more sophisticated algorithm such as the Knuth and Plass TeX';
const firstRow42 = 'Wrap text using a more sophisticated';
```
# --hints--
`wrap` should be a function.
@ -61,24 +79,6 @@ assert.equal(wrapped42.split('\n')[0], firstRow42);
# --seed--
## --after-user-code--
```js
const text =
`Wrap text using a more sophisticated algorithm such as the Knuth and Plass TeX algorithm.
If your language provides this, you get easy extra credit,
but you ''must reference documentation'' indicating that the algorithm
is something better than a simple minimum length algorithm.`;
const wrapped80 = wrap(text, 80);
const wrapped42 = wrap(text, 42);
const firstRow80 =
'Wrap text using a more sophisticated algorithm such as the Knuth and Plass TeX';
const firstRow42 = 'Wrap text using a more sophisticated';
```
## --seed-contents--
```js

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@ -27,41 +27,40 @@ assert.equal(typeof Y((f) => (n) => n), 'function');
factorial(1) should return 1.
```js
var factorial = Y(f => n => (n > 1 ? n * f(n - 1) : 1));
assert.equal(factorial(1), 1);
```
factorial(2) should return 2.
```js
var factorial = Y(f => n => (n > 1 ? n * f(n - 1) : 1));
assert.equal(factorial(2), 2);
```
factorial(3) should return 6.
```js
var factorial = Y(f => n => (n > 1 ? n * f(n - 1) : 1));
assert.equal(factorial(3), 6);
```
factorial(4) should return 24.
```js
var factorial = Y(f => n => (n > 1 ? n * f(n - 1) : 1));
assert.equal(factorial(4), 24);
```
factorial(10) should return 3628800.
```js
var factorial = Y(f => n => (n > 1 ? n * f(n - 1) : 1));
assert.equal(factorial(10), 3628800);
```
# --seed--
## --after-user-code--
```js
var factorial = Y(f => n => (n > 1 ? n * f(n - 1) : 1));
```
## --seed-contents--
```js

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@ -88,41 +88,7 @@ If any pixels were set in this round of either step 1 or step 2 then all steps a
Write a routine to perform Zhang-Suen thinning on the provided `image`, an array of strings, where each string represents single line of the image. In the string, `#` represents black pixel, and whitespace represents white pixel. Function should return thinned image, using the same representation.
# --hints--
`thinImage` should be a function.
```js
assert.equal(typeof thinImage, 'function');
```
`thinImage` should return an array.
```js
assert(Array.isArray(thinImage(_testImage1)));
```
`thinImage` should return an array of strings.
```js
assert.equal(typeof thinImage(_testImage1)[0], 'string');
```
`thinImage(testImage1)` should return a thinned image as in the example.
```js
assert.deepEqual(thinImage(_testImage1), expected1);
```
`thinImage(testImage2)` should return a thinned image.
```js
assert.deepEqual(thinImage(_testImage2), expected2);
```
# --seed--
## --after-user-code--
# --before-each--
```js
const _testImage1 = [
@ -167,7 +133,8 @@ const _testImage2 = [
' ######## ####### ###### ################## ###### ',
' ######## ####### ###### ################ ###### ',
' ######## ####### ###### ############# ###### ',
' '];
' '
];
const expected2 = [
' ',
' ',
@ -190,6 +157,40 @@ const expected2 = [
];
```
# --hints--
`thinImage` should be a function.
```js
assert.equal(typeof thinImage, 'function');
```
`thinImage` should return an array.
```js
assert(Array.isArray(thinImage(_testImage1)));
```
`thinImage` should return an array of strings.
```js
assert.equal(typeof thinImage(_testImage1)[0], 'string');
```
`thinImage(testImage1)` should return a thinned image as in the example.
```js
assert.deepEqual(thinImage(_testImage1), expected1);
```
`thinImage(testImage2)` should return a thinned image.
```js
assert.deepEqual(thinImage(_testImage2), expected2);
```
# --seed--
## --seed-contents--
```js

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@ -24,6 +24,20 @@ For example, for the input `5`, the following result should be produced:
Write a function that takes the size of the zig-zag matrix, and returns the corresponding matrix as two-dimensional array.
# --before-each--
```js
const zm1 = [[0]];
const zm2 = [[0, 1], [2, 3]];
const zm5 = [
[0, 1, 5, 6, 14],
[2, 4, 7, 13, 15],
[3, 8, 12, 16, 21],
[9, 11, 17, 20, 22],
[10, 18, 19, 23, 24]
];
```
# --hints--
ZigZagMatrix should be a function.
@ -64,20 +78,6 @@ assert.deepEqual(ZigZagMatrix(5), zm5);
# --seed--
## --after-user-code--
```js
const zm1 = [[0]];
const zm2 = [[0, 1], [2, 3]];
const zm5 = [
[0, 1, 5, 6, 14],
[2, 4, 7, 13, 15],
[3, 8, 12, 16, 21],
[9, 11, 17, 20, 22],
[10, 18, 19, 23, 24]
];
```
## --seed-contents--
```js

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@ -25,6 +25,27 @@ The sum of the divisors for the first value, **1184**, is **1210** and the sum o
Calculate and show here the Amicable pairs below 20,000 (there are eight).
# --before-each--
```js
const answer300 = [[220, 284]];
const answer3000 = [
[220, 284],
[1184, 1210],
[2620, 2924]
];
const answer20000 = [
[220, 284],
[1184, 1210],
[2620, 2924],
[5020, 5564],
[6232, 6368],
[10744, 10856],
[12285, 14595],
[17296, 18416]
];
```
# --hints--
`amicablePairsUpTo` should be a function.
@ -53,27 +74,6 @@ assert.deepEqual(amicablePairsUpTo(20000), answer20000);
# --seed--
## --after-user-code--
```js
const answer300 = [[220, 284]];
const answer3000 = [
[220, 284],
[1184, 1210],
[2620, 2924]
];
const answer20000 = [
[220, 284],
[1184, 1210],
[2620, 2924],
[5020, 5564],
[6232, 6368],
[10744, 10856],
[12285, 14595],
[17296, 18416]
];
```
## --seed-contents--
```js