diff --git a/curriculum/challenges/chinese/01-responsive-web-design/basic-html-and-html5/nest-an-anchor-element-within-a-paragraph.chinese.md b/curriculum/challenges/chinese/01-responsive-web-design/basic-html-and-html5/nest-an-anchor-element-within-a-paragraph.chinese.md
index 555e7bae4e5..2f56068723b 100644
--- a/curriculum/challenges/chinese/01-responsive-web-design/basic-html-and-html5/nest-an-anchor-element-within-a-paragraph.chinese.md
+++ b/curriculum/challenges/chinese/01-responsive-web-design/basic-html-and-html5/nest-an-anchor-element-within-a-paragraph.chinese.md
@@ -22,7 +22,7 @@ localeTitle: 将 a 嵌套在段落中
通常,文本是被包裹在p段落内:<p> Here's a ... for you to follow. </p>
接下来是anchor a <a>(需要结束标记 </a>):
<a> ... </a>
target是 a 的一个属性,用来指定链接的打开方式。属性值 "_blank" 的意思是链接会在新标签页打开。
-href是 a 的另一个属性:用来指定链接的 URL:<a href="https://freecodecamp.org"> ... </a>
+href是 a 的另一个属性:用来指定链接的 URL:
` ... `
a 元素内的文本:"link to freecodecamp.org",会显示为一个可以点击的链接:
<a href=" ... ">link to freecodecamp.org</a>
例子的最后输出将会是这样:
Here's a link to freecodecamp.org for you to follow.
diff --git a/curriculum/challenges/chinese/02-javascript-algorithms-and-data-structures/basic-data-structures/check-if-an-object-has-a-property.chinese.md b/curriculum/challenges/chinese/02-javascript-algorithms-and-data-structures/basic-data-structures/check-if-an-object-has-a-property.chinese.md index aaaabb1e5d5..3eab10ff7c2 100644 --- a/curriculum/challenges/chinese/02-javascript-algorithms-and-data-structures/basic-data-structures/check-if-an-object-has-a-property.chinese.md +++ b/curriculum/challenges/chinese/02-javascript-algorithms-and-data-structures/basic-data-structures/check-if-an-object-has-a-property.chinese.md @@ -44,7 +44,7 @@ tests: -# Challenge Seed +## Challenge Seed示例文本:
_1111*11111_
应该生成输出:
11111111111111111111
一台简单的图灵机 ,
实施三态繁忙的海狸 。
磁带由0和1组成,状态为A,B,C和H(对于Halt),并且通过在头部所在的字符之前写入状态字母来指示磁头位置。
必须在输入中给出机器操作的初始磁带的所有部分。
除了证明Markov算法是Turing-complete之外,它还让我抓住了C ++实现中的一个错误,这个错误没有被前四个规则集捕获。
图灵机:三态繁忙的海狸 -#sta A,符号0 =>写1,向右移动,新状态BA0 - > 1B +状态A,符号0 =>写1,向右移动,新状态BA0 - > 1B 状态A,符号1 =>写1,向左移动,新状态C0A1 - > C01 1A1 - > C11 状态B,符号0 =>写1,向左移动,新状态A0B0 - > A01