diff --git a/curriculum/challenges/english/15-javascript-algorithms-and-data-structures-22/learn-recursion-by-building-a-decimal-to-binary-converter/64007367d54d2a7efbf44fcf.md b/curriculum/challenges/english/15-javascript-algorithms-and-data-structures-22/learn-recursion-by-building-a-decimal-to-binary-converter/64007367d54d2a7efbf44fcf.md
index 83a95d8f8f0..8b6d0041c29 100644
--- a/curriculum/challenges/english/15-javascript-algorithms-and-data-structures-22/learn-recursion-by-building-a-decimal-to-binary-converter/64007367d54d2a7efbf44fcf.md
+++ b/curriculum/challenges/english/15-javascript-algorithms-and-data-structures-22/learn-recursion-by-building-a-decimal-to-binary-converter/64007367d54d2a7efbf44fcf.md
@@ -19,7 +19,7 @@ isNaN("3.5"); // false
 
 Update the second condition in your `if` statement to use the `isNaN()` function to check if the value returned by `parseInt()` is `NaN`.
 
-Also,as we mentioned in step 1 that we are considering only positive numbers, we should add a third condition in `if` statement to check whether the number is less than 0 (i.e negative numbers)
+Also, as we mentioned in step 1 that we are considering only positive numbers, we should add a third condition in `if` statement to check whether the number is less than 0 (i.e negative numbers).
 
 ```js
  6 < 0; // false